graph the function f(x) = -2x². plot the vertex. then plot another point on the parabola. if you make a…

graph the function f(x) = -2x². plot the vertex. then plot another point on the parabola. if you make a mistake, you can erase your parabola by selecting the second point and placing it on top of the first.

graph the function f(x) = -2x². plot the vertex. then plot another point on the parabola. if you make a mistake, you can erase your parabola by selecting the second point and placing it on top of the first.

Answer

Explanation:

Step1: Identify the vertex

For a quadratic function of the form $y = ax^{2}+bx + c$, in $f(x)=-2x^{2}$, $a=-2$, $b = 0$, $c = 0$. The $x$-coordinate of the vertex is $x=-\frac{b}{2a}=0$. Substitute $x = 0$ into the function: $f(0)=-2\times0^{2}=0$. So the vertex is $(0,0)$.

Step2: Find another point

Let's choose $x = 1$. Substitute $x = 1$ into $f(x)=-2x^{2}$, then $f(1)=-2\times1^{2}=-2$. So another point is $(1, - 2)$.

Answer:

Vertex: $(0,0)$; Another point: $(1,-2)$