graph the function f(x) = 7x². plot the vertex. then plot another point on the parabola. if you make a…

Explanation:

Step1: Identify vertex form

The general form of a parabola is $y = ax^{2}+bx + c$. For the function $f(x)=7x^{2}$, $a = 7$, $b = 0$, $c = 0$. The vertex of a parabola given by $y=ax^{2}+bx + c$ is at the point $(-\frac{b}{2a}, f(-\frac{b}{2a}))$. Since $b = 0$, the $x$-coordinate of the vertex is $x=-\frac{0}{2\times7}=0$.

Step2: Find vertex - y - coordinate

Substitute $x = 0$ into $f(x)=7x^{2}$. Then $f(0)=7\times0^{2}=0$. So the vertex is at the point $(0,0)$.

Step3: Find another point

Let's choose $x = 1$. Substitute $x = 1$ into $f(x)=7x^{2}$. Then $f(1)=7\times1^{2}=7$. So another point on the parabola is $(1,7)$.

The vertex is plotted at the origin $(0,0)$ and the point $(1,7)$ is plotted on the given graph grid to graph the parabola $y = 7x^{2}$.

Answer:

Vertex: $(0,0)$; Another point: $(1,7)$