graph the line that has a slope of 10 and includes the point (-1, -10). click to select points on the graph.

Explanation:

Step1: Use point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $m$ is the slope and $(x_1,y_1)$ is a point on the line. Given $m = 10$, $x_1=-1$ and $y_1=-10$, we have $y+10 = 10(x + 1)$.

Step2: Simplify the equation

Expand the right - hand side: $y+10=10x + 10$. Then subtract 10 from both sides to get $y = 10x$.

Step3: Find another point

Let $x = 1$, then $y=10\times1=10$. So another point on the line is $(1,10)$.

Step4: Graph the line

Plot the points $(-1,-10)$ and $(1,10)$ on the coordinate - plane and draw a straight line passing through them.

Answer:

Plot the points $(-1,-10)$ and $(1,10)$ and draw a line through them.