graph the line that has a slope of 3 and includes the point (-4, -5). click to select points on the graph.
graph the line that has a slope of 3 and includes the point (-4, -5). click to select points on the graph.
Answer
Explanation:
Step1: Find the equation of the line
Use the point - slope form (y - y_1=m(x - x_1)), where (m = 3), (x_1=-4), (y_1=-5). [ \begin{align*} y-(-5)&=3(x - (-4))\ y + 5&=3(x + 4)\ y+5&=3x+12\ y&=3x + 7 \end{align*} ]
Step2: Find another point on the line
Let (x = 0), then (y=3\times0 + 7=7). So another point is ((0,7))
Step3: Plot the points and draw the line
Plot the points ((-4,-5)) and ((0,7)) on the coordinate plane. Then draw a straight line passing through these two points.
Answer:
Plot the point ((-4,-5)). Since the slope (m = 3=\frac{\Delta y}{\Delta x}), from the point ((-4,-5)), move 1 unit to the right (increase (x) by 1) and 3 units up (increase (y) by 3) to get another point ((-3,-2)). You can also use the (y) - intercept form. When (x = 0), (y=7) (from (y = 3x+7)). Plot ((-4,-5)) and ((0,7)) and draw a line through them.