graph this line using the slope and y - intercept:\n\n$y = 8x - 6$\n\nclick to select points on the graph.

graph this line using the slope and y - intercept:\n\n$y = 8x - 6$\n\nclick to select points on the graph.

graph this line using the slope and y - intercept:\n\n$y = 8x - 6$\n\nclick to select points on the graph.

Answer

Answer:

To graph (y = 8x-6) using the slope - intercept form (y=mx + b) (where (m) is the slope and (b) is the (y) - intercept):

  1. Identify the (y) - intercept:
    • For the equation (y = 8x-6), when (x = 0), (y=-6). So, plot the point ((0,-6)) on the graph.
  2. Use the slope to find another point:
    • The slope (m = 8=\frac{8}{1}). From the point ((0,-6)), move (1) unit to the right (increase (x) by (1)) and (8) units up (increase (y) by (8)). This gives the point ((1,2)).
  3. Draw the line:
    • Connect the points ((0,-6)) and ((1,2)) with a straight line. Extend the line in both directions.

Explanation:

Step1: Locate the (y) - intercept

The equation is in the form (y=mx + b). Here (b=-6). So, the line crosses the (y) - axis at the point ((0,-6)).

Step2: Use the slope to find a second point

The slope (m = 8=\frac{\text{rise}}{\text{run}}). Starting from ((0,-6)), with (\text{run}=1) (move (1) unit to the right along the (x) - axis) and (\text{rise}=8) (move (8) units up along the (y) - axis), we get the point ((1,2)).

Step3: Draw the line

Since a straight line is defined by two points, we connect ((0,-6)) and ((1,2)) and extend it. The line (y = 8x-6) is now graphed.