graph the parabola.\n\n$y = 2x^{2}$\n\nplot five points on the parabola: the vertex, two points to the left…

graph the parabola.\n\n$y = 2x^{2}$\n\nplot five points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. then click on the graph - a - function button.

graph the parabola.\n\n$y = 2x^{2}$\n\nplot five points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. then click on the graph - a - function button.

Answer

Explanation:

Step1: Identify the vertex

For the parabola $y = ax^{2}+bx + c$, in the form $y=2x^{2}$ (where $a = 2$, $b = 0$, $c = 0$), the vertex is at $(0,0)$ since the $x$ - coordinate of the vertex is $x=-\frac{b}{2a}=0$ and $y(0)=2\times0^{2}=0$.

Step2: Find points to the left of the vertex

Let $x=-1$, then $y = 2\times(-1)^{2}=2$. Let $x = - 2$, then $y=2\times(-2)^{2}=8$.

Step3: Find points to the right of the vertex

Let $x = 1$, then $y=2\times1^{2}=2$. Let $x = 2$, then $y=2\times2^{2}=8$.

Answer:

The five points are $(0,0),(-1,2),(-2,8),(1,2),(2,8)$