which graph represents y = √x?

Explanation:

Step1: Analyze domain of function

The function $y = \sqrt{x}$ has domain $x\geq0$ since we can't take the square - root of a negative number in the real - number system.

Step2: Analyze some key points

When $x = 0$, $y=\sqrt{0}=0$; when $x = 1$, $y=\sqrt{1}=1$; when $x = 4$, $y=\sqrt{4}=2$. The graph of $y = \sqrt{x}$ is a curve that starts at the origin $(0,0)$ and increases as $x$ increases for non - negative $x$ values.

Answer:

The graph that starts at the origin $(0,0)$ and is only in the first quadrant (since $x\geq0$ and $y\geq0$) and has a curve shape increasing as $x$ increases is the correct graph for $y = \sqrt{x}$. Without seeing all the options fully, the graph should have the following characteristics: it is a non - negative valued curve starting at the point $(0,0)$ and defined only for $x\geq0$.