which graph represents the function $f(x)=(x - 3)^2$?

Explanation:

Step1: Recall vertex - form of a parabola

The general vertex - form of a parabola is $y=a(x - h)^2+k$, where $(h,k)$ is the vertex of the parabola. For the function $f(x)=(x - 3)^2$, we have $a = 1$, $h=3$ and $k = 0$.

Step2: Determine the vertex

Since $h = 3$ and $k=0$, the vertex of the parabola $y=(x - 3)^2$ is at the point $(3,0)$. Also, since $a=1>0$, the parabola opens upwards.

Answer:

The graph with a vertex at the point $(3,0)$ and opening upwards.