which graph represents the function f(x)=(x - 3)^2?

Explanation:

Step1: Recall vertex - form of a parabola

The vertex - form of a parabola is $y=a(x - h)^2+k$, where $(h,k)$ is the vertex of the parabola. For the function $f(x)=(x - 3)^2$, we have $a = 1$, $h=3$, and $k = 0$.

Step2: Analyze the vertex

Since $h = 3$ and $k=0$, the vertex of the parabola $y=(x - 3)^2$ is at the point $(3,0)$. Also, since $a=1>0$, the parabola opens upwards.

Answer:

The graph with a vertex at the point $(3,0)$ and opening upwards. (Without specific labels for each graph, we can't point to a particular one among the given options by name, but it should be the one with vertex at $(3,0)$ and opening upwards)