which graph represents the solution set of the compound inequality -4 ≤ 3x - 1 and 2x + 4 ≤ 18?

Explanation:

Step1: Solve the first - inequality

Solve $-4\leq3x - 1$. Add 1 to both sides: $-4 + 1\leq3x-1 + 1$, which simplifies to $-3\leq3x$. Then divide both sides by 3: $\frac{-3}{3}\leq\frac{3x}{3}$, so $-1\leq x$.

Step2: Solve the second - inequality

Solve $2x + 4\leq18$. Subtract 4 from both sides: $2x+4 - 4\leq18 - 4$, which simplifies to $2x\leq14$. Then divide both sides by 2: $\frac{2x}{2}\leq\frac{14}{2}$, so $x\leq7$.

Step3: Combine the solutions

The solution of the compound - inequality is $-1\leq x\leq7$. On a number line, this is represented by a closed circle at $x=-1$, a closed circle at $x = 7$, and a line segment connecting them.

Answer:

The first graph (assuming the first graph has a closed - circle at $x=-1$, a closed - circle at $x = 7$, and a line segment between them)