graph the system on a separate sheet of paper and determine the number of solutions it has. if it has one…

graph the system on a separate sheet of paper and determine the number of solutions it has. if it has one solution, determine its coordinates.\n$y = 4x + 2$\n$y = -2x - 4$\na) infinitely many solutions\nb) 1 solution; $(-1, 0)$\nc) no solution\nd) 1 solution; $(-1, -2)$

graph the system on a separate sheet of paper and determine the number of solutions it has. if it has one solution, determine its coordinates.\n$y = 4x + 2$\n$y = -2x - 4$\na) infinitely many solutions\nb) 1 solution; $(-1, 0)$\nc) no solution\nd) 1 solution; $(-1, -2)$

Answer

Explanation:

Step1: Set the equations equal

Set (4x + 2=-2x-4).

Step2: Solve for (x)

Add (2x) to both sides: (4x+2x + 2=-4), so (6x+2=-4). Subtract (2) from both sides: (6x=-4 - 2=-6). Divide by (6): (x=\frac{-6}{6}=-1).

Step3: Solve for (y)

Substitute (x = - 1) into (y = 4x+2): (y=4\times(-1)+2=-4 + 2=-2).

Answer:

D. 1 solution; ((-1,-2))