haji rows his canoe 10 mph in still water. he noticed one day that he could row 4 miles upstream in the same…

haji rows his canoe 10 mph in still water. he noticed one day that he could row 4 miles upstream in the same amount of time he could row 6 miles downstream. what was the approximate speed of the current that day?\n2.0 mph\n3.3 mph\n5.0 mph\n10.0 mph

haji rows his canoe 10 mph in still water. he noticed one day that he could row 4 miles upstream in the same amount of time he could row 6 miles downstream. what was the approximate speed of the current that day?\n2.0 mph\n3.3 mph\n5.0 mph\n10.0 mph

Answer

Explanation:

Step1: Set up speed - time equations

Let the speed of the current be $x$ mph. The speed of the canoe upstream is $(10 - x)$ mph and downstream is $(10 + x)$ mph. Since time $t=\frac{d}{s}$ (where $d$ is distance and $s$ is speed), and the time upstream $t_{up}$ and downstream $t_{down}$ are equal, we have $\frac{4}{10 - x}=\frac{6}{10 + x}$.

Step2: Cross - multiply

Cross - multiplying the equation $\frac{4}{10 - x}=\frac{6}{10 + x}$ gives $4(10 + x)=6(10 - x)$.

Step3: Expand both sides

Expanding, we get $40+4x = 60-6x$.

Step4: Solve for $x$

Add $6x$ to both sides: $40 + 4x+6x=60-6x + 6x$, which simplifies to $40 + 10x=60$. Then subtract 40 from both sides: $10x=60 - 40$, so $10x = 20$. Divide both sides by 10: $x = 2$.

Answer:

A. 2.0 mph