helaine graphed the equation 12x - 4y = 3. what was the slope of helaines line?\n-12\n-4\n3\n12

helaine graphed the equation 12x - 4y = 3. what was the slope of helaines line?\n-12\n-4\n3\n12

helaine graphed the equation 12x - 4y = 3. what was the slope of helaines line?\n-12\n-4\n3\n12

Answer

Explanation:

Step1: Rewrite in slope - intercept form

The slope - intercept form is $y = mx + b$, where $m$ is the slope. Start with $12x-4y = 3$. First, isolate $y$: $-4y=-12x + 3$.

Step2: Solve for $y$

Divide each term by $-4$: $y=\frac{-12x}{-4}+\frac{3}{-4}$, which simplifies to $y = 3x-\frac{3}{4}$.

Answer:

C. 3