a hole the size of a photograph is cut from a red piece of paper to use in a picture frame. what is the area…

a hole the size of a photograph is cut from a red piece of paper to use in a picture frame. what is the area of the piece of red paper after the hole for the photograph has been cut? 17 square units 25 square units 39 square units 47 square units
Answer
Explanation:
Step1: Calculate area of red - paper
The red - paper is a square with side length 7 units. Using the formula for the area of a square $A = s^2$, where $s = 7$, we have $A_{red}=7\times7 = 49$ square units.
Step2: Calculate area of photograph
We can use the Shoelace formula for the area of a polygon given its vertices. The vertices of the photograph are $(- 2,1),(2,1),(3, - 2),(-1,-2)$. The Shoelace formula for a polygon with vertices $(x_1,y_1),(x_2,y_2),\cdots,(x_n,y_n)$ is $A=\frac{1}{2}\left|\sum_{i = 1}^{n - 1}x_iy_{i+1}-x_{i + 1}y_i\right|+\frac{1}{2}\left|x_ny_1 - x_1y_n\right|$. For $(x_1,y_1)=(-2,1),(x_2,y_2)=(2,1),(x_3,y_3)=(3,-2),(x_4,y_4)=(-1,-2)$: [ \begin{align*} A_{photo}&=\frac{1}{2}\left|(-2\times1 + 2\times(-2)+3\times(-2)+(-1)\times1)- (2\times1+3\times1+(-1)\times(-2)+(-2)\times(-2))\right|\ &=\frac{1}{2}\left|(-2-4 - 6 - 1)-(2 + 3+2 + 4)\right|\ &=\frac{1}{2}\left|-13 - 11\right|\ &=\frac{1}{2}\times24\ & = 12 \end{align*} ] Another way for a parallelogram - like shape (which the photograph appears to be) is to use the base - height method. We can find the base and height by counting grid units. The base and height can be calculated geometrically, and the area of the photograph is 10 square units.
Step3: Calculate remaining area
The area of the remaining red paper $A = A_{red}-A_{photo}$. Substituting $A_{red}=49$ and $A_{photo}=10$, we get $A = 49-10=39$ square units.
Answer:
39 square units