what is the horizontal asymptote of $f(x)=\frac{-2x}{x + 1}$?\n$y=-2$\n$y=-1$\n$y = 0$\n$y=1$
what is the horizontal asymptote of $f(x)=\frac{-2x}{x + 1}$?\n$y=-2$\n$y=-1$\n$y = 0$\n$y=1$
Answer
Explanation:
Step1: Recall horizontal - asymptote rule
For a rational function $f(x)=\frac{a_nx^n+\cdots+a_0}{b_mx^m+\cdots + b_0}$, when $n = m$, the horizontal asymptote is $y=\frac{a_n}{b_m}$. Here, $f(x)=\frac{-2x}{x + 1}$, where $n = 1$ (degree of numerator), $m = 1$ (degree of denominator), $a_1=-2$, $b_1 = 1$.
Step2: Calculate the horizontal - asymptote
$y=\frac{-2}{1}=-2$.
Answer:
A. $y = - 2$