hugh bought some magazines that cost $3.95 each and some books that cost $8.95 each. he spent a total of…

hugh bought some magazines that cost $3.95 each and some books that cost $8.95 each. he spent a total of $47.65. if hugh bought 3 magazines, how many books did he buy? the equation that models the problem is 3.95m + 8.95b = 47.65, where m is the number of magazines and b is the number of books.

hugh bought some magazines that cost $3.95 each and some books that cost $8.95 each. he spent a total of $47.65. if hugh bought 3 magazines, how many books did he buy? the equation that models the problem is 3.95m + 8.95b = 47.65, where m is the number of magazines and b is the number of books.

Answer

Answer:

4

Explanation:

Step1: Sustituir el valor de m

Dado que $m = 3$, sustituimos en la ecuación $3.95m+8.95b = 47.65$. Tenemos $3.95\times3+8.95b=47.65$.

Step2: Calcular el primer término

$3.95\times3 = 11.85$, entonces la ecuación se convierte en $11.85 + 8.95b=47.65$.

Step3: Isolar el término con b

Restamos 11.85 de ambos lados: $8.95b=47.65 - 11.85$.

Step4: Calcular el lado derecho

$47.65 - 11.85=35.8$. Así, $8.95b = 35.8$.

Step5: Resolver para b

Dividimos ambos lados por 8.95: $b=\frac{35.8}{8.95}=4$.