identify the vertex of the quadratic equation in vertex form: $y = -2(x + 3)^2 + 5$

identify the vertex of the quadratic equation in vertex form: $y = -2(x + 3)^2 + 5$

identify the vertex of the quadratic equation in vertex form: $y = -2(x + 3)^2 + 5$

Answer

Explanation:

Step1: Recall the vertex form of a quadratic equation

The vertex form of a quadratic equation is (y = a(x - h)^2 + k), where ((h,k)) is the vertex.

Step2: Rewrite the given equation to match the vertex form

Given (y=-2(x + 3)^2+5), we can rewrite it as (y=-2(x-(- 3))^2 + 5).

Step3: Identify (h) and (k)

Comparing with (y = a(x - h)^2 + k), we have (h=-3) and (k = 5).

Answer:

((-3,5)) (the fourth option)