iliana multiplied 3p - 7 and 2p² - 3p - 4. her work is shown in the table. (3p - 7)(2p² - 3p - 4) which is…

iliana multiplied 3p - 7 and 2p² - 3p - 4. her work is shown in the table. (3p - 7)(2p² - 3p - 4) which is the product? 6p³ + 23p² + 9p + 28 6p³ - 23p² - 9p + 28 6p³ - 23p² + 9p + 28 6p³ + 23p² - 9p + 28

iliana multiplied 3p - 7 and 2p² - 3p - 4. her work is shown in the table. (3p - 7)(2p² - 3p - 4) which is the product? 6p³ + 23p² + 9p + 28 6p³ - 23p² - 9p + 28 6p³ - 23p² + 9p + 28 6p³ + 23p² - 9p + 28

Answer

Explanation:

Step1: Combine like - terms

Combine the $p^{2}$ terms: $-9p^{2}-14p^{2}=-23p^{2}$ Combine the $p$ terms: $-12p + 21p=9p$ The product of the two polynomials $(3p - 7)(2p^{2}-3p - 4)$ from the table elements is $6p^{3}-9p^{2}-12p-14p^{2}+21p + 28$.

Step2: Write the final polynomial

$6p^{3}+(-9p^{2}-14p^{2})+(-12p + 21p)+28=6p^{3}-23p^{2}+9p + 28$

Answer:

$6p^{3}-23p^{2}+9p + 28$