what is the initial value of the exponential function represented by the table?\n-2 $\frac{1}{8}$\n-1…

what is the initial value of the exponential function represented by the table?\n-2 $\frac{1}{8}$\n-1 $\frac{1}{4}$\n0 $\frac{1}{2}$\n1 1\n2 2\n$\frac{1}{8}$\n$\frac{1}{4}$\n$\frac{1}{2}$\n1

what is the initial value of the exponential function represented by the table?\n-2 $\frac{1}{8}$\n-1 $\frac{1}{4}$\n0 $\frac{1}{2}$\n1 1\n2 2\n$\frac{1}{8}$\n$\frac{1}{4}$\n$\frac{1}{2}$\n1

Answer

Explanation:

Step1: Recall initial - value concept

The initial value of an exponential function is the value of the function when (x = 0).

Step2: Find the value of (f(x)) at (x = 0)

From the table, when (x=0), (f(0)=\frac{1}{2}).

Answer:

(\frac{1}{2})