what is the y - intercept of the function $f(x)=-\frac{2}{9}x+\frac{1}{3}$?\n$-\frac{2}{9}$\n$-\frac{1}{3}$\n…

what is the y - intercept of the function $f(x)=-\frac{2}{9}x+\frac{1}{3}$?\n$-\frac{2}{9}$\n$-\frac{1}{3}$\n$\frac{1}{3}$\n$\frac{2}{9}$

what is the y - intercept of the function $f(x)=-\frac{2}{9}x+\frac{1}{3}$?\n$-\frac{2}{9}$\n$-\frac{1}{3}$\n$\frac{1}{3}$\n$\frac{2}{9}$

Answer

Explanation:

Step1: Recall y - intercept formula

The y - intercept of a linear function $y = mx + b$ is the value of $y$ when $x = 0$.

Step2: Substitute $x = 0$ into the function

Given $f(x)=-\frac{2}{9}x+\frac{1}{3}$, when $x = 0$, we have $f(0)=-\frac{2}{9}\times0+\frac{1}{3}$. Since $-\frac{2}{9}\times0 = 0$, then $f(0)=\frac{1}{3}$.

Answer:

C. $\frac{1}{3}$