what is the y - intercept of the function $f(x)=-\frac{2}{9}x+\frac{1}{3}$?\n$\frac{2}{9}$\n$\frac{1}{3}$\n$\…

what is the y - intercept of the function $f(x)=-\frac{2}{9}x+\frac{1}{3}$?\n$\frac{2}{9}$\n$\frac{1}{3}$\n$\frac{1}{3}$\n$\frac{2}{9}$

what is the y - intercept of the function $f(x)=-\frac{2}{9}x+\frac{1}{3}$?\n$\frac{2}{9}$\n$\frac{1}{3}$\n$\frac{1}{3}$\n$\frac{2}{9}$

Answer

Explanation:

Step1: Recall y - intercept concept

The y - intercept of a linear function (y = f(x)=mx + b) is the value of (y) when (x = 0).

Step2: Substitute (x = 0) into the function

Given (f(x)=-\frac{2}{9}x+\frac{1}{3}), when (x = 0), we have (f(0)=-\frac{2}{9}\times0+\frac{1}{3}). Since (-\frac{2}{9}\times0 = 0), then (f(0)=\frac{1}{3}).

Answer:

(\frac{1}{3})