what is the x - intercept of the graph of the function ( f(x)=x^{2}-16x + 64 )?\n( (-8,0) )\n( (0,8) )\n(…

what is the x - intercept of the graph of the function ( f(x)=x^{2}-16x + 64 )?\n( (-8,0) )\n( (0,8) )\n( (8,0) )\n( (0,-8) )

what is the x - intercept of the graph of the function ( f(x)=x^{2}-16x + 64 )?\n( (-8,0) )\n( (0,8) )\n( (8,0) )\n( (0,-8) )

Answer

Explanation:

Step1: Find the x - intercept

Set (y = f(x)=0), so (x^{2}-16x + 64=0).

Step2: Factor the quadratic equation

We know that (a^{2}-2ab + b^{2}=(a - b)^{2}). Here (a=x), (b = 8), so (x^{2}-16x + 64=(x - 8)^{2}). Then ((x - 8)^{2}=0).

Step3: Solve for x

Take the square root of both sides: (x-8=0), so (x = 8).

Answer:

C. ((8,0))