what are the x - intercepts of the graph of the function f(x)=x² + 4x - 12? (-6,0),(2,0) (-2,-16),(0,-12)…
what are the x - intercepts of the graph of the function f(x)=x² + 4x - 12? (-6,0),(2,0) (-2,-16),(0,-12) (-6,0),(-2,-16),(2,0) (0,-12),(-6,0),(2,0)
Answer
Answer:
A. (-6, 0), (2, 0)
Explanation:
Step1: Set function equal to 0
$x^{2}+4x - 12=0$
Step2: Factor the quadratic
$(x + 6)(x - 2)=0$
Step3: Solve for x
$x+6 = 0$ gives $x=-6$; $x - 2=0$ gives $x = 2$ So the x - intercepts are (-6, 0) and (2, 0).