if $g(x)$ is the inverse of $f(x)$ and $f(x)=4x + 12$, what is $g(x)$?\n$g(x)=12x + 4$\n$g(x)=\frac{1}{4}x-12…
if $g(x)$ is the inverse of $f(x)$ and $f(x)=4x + 12$, what is $g(x)$?\n$g(x)=12x + 4$\n$g(x)=\frac{1}{4}x-12$\n$g(x)=x - 3$\n$g(x)=\frac{1}{4}x-3$
Answer
Explanation:
Step1: Let $y = f(x)$
$y = 4x+12$
Step2: Solve for $x$ in terms of $y$
$y-12 = 4x$, then $x=\frac{y - 12}{4}=\frac{1}{4}y-3$
Step3: Replace $y$ with $x$ to get the inverse function
Since $g(x)$ is the inverse of $f(x)$, $g(x)=\frac{1}{4}x - 3$
Answer:
$g(x)=\frac{1}{4}x - 3$