what is the inverse of the function $f(x)=2x + 1$?\n$h(x)=\frac{1}{2}x-\frac{1}{2}$\n$h(x)=\frac{1}{2}x+\frac…

what is the inverse of the function $f(x)=2x + 1$?\n$h(x)=\frac{1}{2}x-\frac{1}{2}$\n$h(x)=\frac{1}{2}x+\frac{1}{2}$\n$h(x)=\frac{1}{2}x - 2$\n$h(x)=\frac{1}{2}x+2$

what is the inverse of the function $f(x)=2x + 1$?\n$h(x)=\frac{1}{2}x-\frac{1}{2}$\n$h(x)=\frac{1}{2}x+\frac{1}{2}$\n$h(x)=\frac{1}{2}x - 2$\n$h(x)=\frac{1}{2}x+2$

Answer

Answer:

A. $h(x)=\frac{1}{2}x - \frac{1}{2}$

Explanation:

Step1: Let $y = f(x)$

$y = 2x+1$

Step2: Swap $x$ and $y$

$x = 2y + 1$

Step3: Solve for $y$

$x-1=2y$ $y=\frac{1}{2}x-\frac{1}{2}$ So the inverse function $h(x)=\frac{1}{2}x - \frac{1}{2}$