what is the inverse of the function $f(x)=4x + 8$?\n$h(x)=\frac{1}{4}x - 2$\n$h(x)=\frac{1}{4}x +…

Explanation:

Step1: Set $y = f(x)$

Let $y = 4x + 8$.

Step2: Solve for $x$ in terms of $y$

First, subtract 8 from both sides: $y - 8=4x$. Then divide both sides by 4, we get $x=\frac{y - 8}{4}=\frac{1}{4}y - 2$.

Step3: Replace $x$ with $f^{-1}(x)$ and $y$ with $x$

The inverse function $f^{-1}(x)=\frac{1}{4}x - 2$.

Answer:

A. $h(x)=\frac{1}{4}x - 2$