what is the inverse of the function ( f(x)=4x + 8 )?\n( h(x)=\frac{1}{4}x - 2 )\n( h(x)=\frac{1}{4}x + 2…
what is the inverse of the function ( f(x)=4x + 8 )?\n( h(x)=\frac{1}{4}x - 2 )\n( h(x)=\frac{1}{4}x + 2 )\n( h(x)=\frac{1}{2}x - 2 )\n( h(x)=\frac{1}{2}x + 2 )
Answer
Explanation:
Step1: Replace (f(x)) with (y)
(y = 4x+8)
Step2: Swap (x) and (y)
(x = 4y + 8)
Step3: Solve for (y)
Subtract (8) from both sides: (x - 8=4y). Then divide both sides by (4): (y=\frac{1}{4}x - 2)
Answer:
(h(x)=\frac{1}{4}x - 2) (the first option)