what is the inverse of the function $f(x)=\frac{1}{9}x + 2$?\n$h(x)=18x - 2$\n$h(x)=9x - 18$\n$h(x)=9x +…

Answer:

B. $h(x)=9x - 18$

Explanation:

Step1: Let $y = f(x)$

$y=\frac{1}{9}x + 2$

Step2: Swap $x$ and $y$

$x=\frac{1}{9}y + 2$

Step3: Solve for $y$

First, subtract 2 from both sides: $x - 2=\frac{1}{9}y$. Then multiply both sides by 9: $y = 9(x - 2)=9x-18$. So the inverse function $h(x)=9x - 18$.