what is the inverse of the function (f(x)=x + 3)?\n(h(x)=\frac{1}{3}x + 3)\n(h(x)=\frac{1}{3}x-3)\n(h(x)=x…
what is the inverse of the function (f(x)=x + 3)?\n(h(x)=\frac{1}{3}x + 3)\n(h(x)=\frac{1}{3}x-3)\n(h(x)=x - 3)\n(h(x)=x + 3)
Answer
Answer:
C. $h(x)=x - 3$
Explanation:
Step1: Let $y = f(x)$
$y=x + 3$
Step2: Swap $x$ and $y$
$x=y + 3$
Step3: Solve for $y$
$y=x - 3$ So the inverse function $h(x)=x - 3$.