what is the inverse of the function ( f(x)=x + 3 )?\n( h(x)=\frac{1}{3}x + 3 )\n( h(x)=\frac{1}{3}x - 3 )\n(…

what is the inverse of the function ( f(x)=x + 3 )?\n( h(x)=\frac{1}{3}x + 3 )\n( h(x)=\frac{1}{3}x - 3 )\n( h(x)=x - 3 )\n( h(x)=x + 3 )

what is the inverse of the function ( f(x)=x + 3 )?\n( h(x)=\frac{1}{3}x + 3 )\n( h(x)=\frac{1}{3}x - 3 )\n( h(x)=x - 3 )\n( h(x)=x + 3 )

Answer

Explanation:

Step1: Let ( y = f(x) )

( y=x + 3 )

Step2: Swap ( x ) and ( y )

( x=y + 3 )

Step3: Solve for ( y )

Subtract ( 3 ) from both sides: ( y=x - 3 )

Answer:

( h(x)=x - 3 ) (the third option)