for the inverse variation equation xy = k, what is the value of x when y = 4 and k = 7?\n\\(\\frac{4}{7}\\)\n…

for the inverse variation equation xy = k, what is the value of x when y = 4 and k = 7?\n\\(\\frac{4}{7}\\)\n\\(\\frac{7}{4}\\)\n3\n28

for the inverse variation equation xy = k, what is the value of x when y = 4 and k = 7?\n\\(\\frac{4}{7}\\)\n\\(\\frac{7}{4}\\)\n3\n28

Answer

Explanation:

Step1: Substitute given values

Given $xy = k$, substitute $y = 4$ and $k = 7$ into the equation, getting $x\times4=7$.

Step2: Solve for x

Divide both sides of the equation $4x = 7$ by 4, so $x=\frac{7}{4}$.

Answer:

B. $\frac{7}{4}$