jillians school is selling tickets for a play. the tickets cost $10.50 for adults and $3.75 for students…

jillians school is selling tickets for a play. the tickets cost $10.50 for adults and $3.75 for students. the ticket sales for opening night totaled $2071.50. the equation 10.50a + 3.75b = 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. if 82 students attended, how may adult tickets were sold? adult tickets

jillians school is selling tickets for a play. the tickets cost $10.50 for adults and $3.75 for students. the ticket sales for opening night totaled $2071.50. the equation 10.50a + 3.75b = 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. if 82 students attended, how may adult tickets were sold? adult tickets

Answer

Explanation:

Step1: Substitute student - ticket number

Given $b = 82$, substitute it into the equation $10.50a+3.75b = 2071.50$. We get $10.50a+3.75\times82=2071.50$.

Step2: Calculate the value of $3.75\times82$

$3.75\times82 = 307.5$. So the equation becomes $10.50a+307.5 = 2071.50$.

Step3: Isolate the term with $a$

Subtract 307.5 from both sides of the equation: $10.50a=2071.50 - 307.5$. $10.50a=1764$.

Step4: Solve for $a$

Divide both sides of the equation by 10.50: $a=\frac{1764}{10.50}=168$.

Answer:

168