jim measures the height of a volleyball net to be 82 in, but its actual height is 92 in. what is the percent…

jim measures the height of a volleyball net to be 82 in, but its actual height is 92 in. what is the percent error in jims measurement? round to the nearest whole percent.

jim measures the height of a volleyball net to be 82 in, but its actual height is 92 in. what is the percent error in jims measurement? round to the nearest whole percent.

Answer

Explanation:

Step1: Find the error amount

Error = |Measured - Actual| = |82 - 92|= 10

Step2: Calculate percent - error formula

Percent error=$\frac{\text{Error}}{\text{Actual}}\times100%=\frac{10}{92}\times100%$

Step3: Evaluate and round

$\frac{10}{92}\times100%\approx10.87%$. Rounding to the nearest whole percent gives 11%.

Answer:

11%