john has 48 square centimeter tiles he wants to use to create a mosaic. he wants the mosaic to be…
john has 48 square centimeter tiles he wants to use to create a mosaic. he wants the mosaic to be rectangular with a length that is 2 centimeters longer than the width. which equation could john solve to find w, the greatest width in centimeters he can use for the mosaic? o w(w - 2)=48 o w(w + 2)=48 o 2w(w - 2)=48 o 2w(w + 2)=48
Answer
Explanation:
Step1: Recall rectangle - area formula
The area formula of a rectangle is $A = l\times w$, where $A$ is the area, $l$ is the length, and $w$ is the width.
Step2: Express length in terms of width
Given that the length $l$ is 2 centimeters longer than the width $w$, so $l=w + 2$.
Step3: Substitute into area formula
The area $A = 48$ square - centimeters. Substituting $l = w + 2$ and $A = 48$ into $A=l\times w$, we get $48=(w + 2)\times w$, which can be written as $w(w + 2)=48$.
Answer:
$w(w + 2)=48$ (the second option)