john has 48 square - centimeter tiles he wants to use to create a mosaic. he wants the mosaic to be…
john has 48 square - centimeter tiles he wants to use to create a mosaic. he wants the mosaic to be rectangular with a length that is 2 centimeters longer than the width. which equation could john solve to find w, the greatest width in centimeters he can use for the mosaic? w(w - 2)=48 w(w + 2)=48 2w(w - 2)=48 2w(w + 2)=48
Answer
Explanation:
Step1: Recall area formula
The area of a rectangle is $A = lw$, where $l$ is the length and $w$ is the width. Given that the length $l$ is 2 centimeters longer than the width, so $l=w + 2$, and the area $A = 48$ square - centimeters.
Step2: Substitute into formula
Substitute $l = w + 2$ and $A = 48$ into the area formula $A=lw$. We get $48=(w + 2)w$, which can be rewritten as $w(w + 2)=48$.
Answer:
$w(w + 2)=48$ (the second option)