john has 48 square centimeter tiles he wants to use to create a mosaic. he wants the mosaic to be…

john has 48 square centimeter tiles he wants to use to create a mosaic. he wants the mosaic to be rectangular with a length that is 2 centimeters longer than the width. which equation could john solve to find w, the greatest width in centimeters he can use for the mosaic? w(w - 2) = 48 w(w + 2) = 48 2w(w - 2) = 48 2w(w + 2) = 48

john has 48 square centimeter tiles he wants to use to create a mosaic. he wants the mosaic to be rectangular with a length that is 2 centimeters longer than the width. which equation could john solve to find w, the greatest width in centimeters he can use for the mosaic? w(w - 2) = 48 w(w + 2) = 48 2w(w - 2) = 48 2w(w + 2) = 48

Answer

Explanation:

Step1: Define variables

Let the width of the rectangle be $w$ cm. Since the length is 2 centimeters longer than the width, the length is $(w + 2)$ cm.

Step2: Use area - formula

The area of a rectangle is $A=\text{length}\times\text{width}$. The area of the mosaic is 48 square - centimeters. So, $A = w(w + 2)$. And we know $A = 48$. Thus, the equation is $w(w + 2)=48$.

Answer:

B. $w(w + 2)=48$