jonas jogged up the hill at an average rate of $\frac{1}{12}$ of a mile per minute and then walked down the…

jonas jogged up the hill at an average rate of $\frac{1}{12}$ of a mile per minute and then walked down the hill at an average rate of $\frac{1}{16}$ of a mile per minute. the round - trip took him 42 minutes. what is the missing value in the table that represents the distance of the trip down the hill?\n| | rate (mi/min) | time (min) | distance (mi) |\n|--|--|--|--| \n| up the hill | $\frac{1}{12}$ | $x$ | $\frac{1}{12}x$ |\n| down the hill | $\frac{1}{16}$ | $42 - x$ |? |

jonas jogged up the hill at an average rate of $\frac{1}{12}$ of a mile per minute and then walked down the hill at an average rate of $\frac{1}{16}$ of a mile per minute. the round - trip took him 42 minutes. what is the missing value in the table that represents the distance of the trip down the hill?\n| | rate (mi/min) | time (min) | distance (mi) |\n|--|--|--|--| \n| up the hill | $\frac{1}{12}$ | $x$ | $\frac{1}{12}x$ |\n| down the hill | $\frac{1}{16}$ | $42 - x$ |? |

Answer

Answer:

$\frac{1}{16}(42 - x)$

Explanation:

Step1: Recall distance - rate - time formula

$d=rt$ (where $d$ is distance, $r$ is rate, $t$ is time)

Step2: Identify rate and time for down - hill

Rate $r = \frac{1}{16}$ mi/min, time $t=42 - x$ min

Step3: Calculate distance

$d=\frac{1}{16}(42 - x)$ mi