when justin left his house this morning, his cell phone was 50% charged and it then started to lose 5%…
when justin left his house this morning, his cell phone was 50% charged and it then started to lose 5% charge for each hour thereafter. write an equation for b, in terms of t, representing the charge remaining in justins battery, as a percentage, t hours after justin left his house.\n\n|number of hours since justin left his house|percentage charge remaining on phone battery|\n|----|----|\n|0|\n|1|\n|2|\n|3|\n\nanswer attempt 1 out of 2\n\nyou must answer all questions above in order to submit.
Answer
Explanation:
Step1: Identify the initial value
The initial charge is 50%, so when $t = 0$, $B=50$.
Step2: Determine the rate of change
The battery loses 5% charge per hour. So the change in charge per hour is - 5.
Step3: Write the linear - equation formula
The general form of a linear equation is $y=mx + b$, where $m$ is the slope and $b$ is the y - intercept. In our case, $B$ is the dependent variable (percentage of charge remaining), $t$ is the independent variable (number of hours), $m=-5$ and $b = 50$. So the equation is $B=50-5t$.
Answer:
$B = 50-5t$