karissa begins to solve the equation $\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$. her work is correct and…

karissa begins to solve the equation $\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$. her work is correct and is shown below. $\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$ $\frac{1}{2}x-7 + 11=\frac{1}{2}x-x + 4$ $\frac{1}{2}x+4=-\frac{1}{2}x + 4$ when she subtracts 4 from both sides, $\frac{1}{2}x=-\frac{1}{2}x$ results. what is the value of $x$? -1 $-\frac{1}{2}$ 0 $\frac{1}{2}$

karissa begins to solve the equation $\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$. her work is correct and is shown below. $\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$ $\frac{1}{2}x-7 + 11=\frac{1}{2}x-x + 4$ $\frac{1}{2}x+4=-\frac{1}{2}x + 4$ when she subtracts 4 from both sides, $\frac{1}{2}x=-\frac{1}{2}x$ results. what is the value of $x$? -1 $-\frac{1}{2}$ 0 $\frac{1}{2}$

Answer

Answer:

C. 0

Explanation:

Step1: Start with the equation after subtracting 4 from both sides

$\frac{1}{2}x=-\frac{1}{2}x$

Step2: Add $\frac{1}{2}x$ to both sides

$\frac{1}{2}x+\frac{1}{2}x = -\frac{1}{2}x+\frac{1}{2}x$ $x = 0$