karissa begins to solve the equation $\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$. her work is correct and…

karissa begins to solve the equation $\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$. her work is correct and is shown below.\n$\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$\n$\frac{1}{2}x-7 + 11=\frac{1}{2}x-x + 4$\n$\frac{1}{2}x+4=-\frac{1}{2}x + 4$\nwhen she subtracts 4 from both sides, $\frac{1}{2}x=-\frac{1}{2}x$ results. what is the value of $x$?\n-1\n$-\frac{1}{2}$\n0\n$\frac{1}{2}$

karissa begins to solve the equation $\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$. her work is correct and is shown below.\n$\frac{1}{2}(x - 14)+11=\frac{1}{2}x-(x - 4)$\n$\frac{1}{2}x-7 + 11=\frac{1}{2}x-x + 4$\n$\frac{1}{2}x+4=-\frac{1}{2}x + 4$\nwhen she subtracts 4 from both sides, $\frac{1}{2}x=-\frac{1}{2}x$ results. what is the value of $x$?\n-1\n$-\frac{1}{2}$\n0\n$\frac{1}{2}$

Answer

Explanation:

Step1: Start with the equation

We have $\frac{1}{2}x + 4=-\frac{1}{2}x + 4$.

Step2: Add $\frac{1}{2}x$ to both sides

$\frac{1}{2}x+\frac{1}{2}x + 4=-\frac{1}{2}x+\frac{1}{2}x + 4$, which simplifies to $x + 4=4$.

Step3: Subtract 4 from both sides

$x+4 - 4=4 - 4$, so $x = 0$.

Answer:

0