kathleen and arnob both run from the park entrance along a loop. kathleen starts walking from the park…

kathleen and arnob both run from the park entrance along a loop. kathleen starts walking from the park entrance and gets a 5 - mile head start on arnob. the graph shows how far they have both traveled. how many minutes does it take arnob to catch up to kathleen? 9.8 10 73.5 75

kathleen and arnob both run from the park entrance along a loop. kathleen starts walking from the park entrance and gets a 5 - mile head start on arnob. the graph shows how far they have both traveled. how many minutes does it take arnob to catch up to kathleen? 9.8 10 73.5 75

Answer

Explanation:

Step1: Identificar las ecuaciones

Tenemos la ecuación de la distancia de Kathleen $y=\frac{1}{15}x + 5$ y la de Arnob $y=\frac{2}{15}x$. Cuando Arnob alcanza a Kathleen, sus distancias son iguales, es decir, $\frac{1}{15}x+5=\frac{2}{15}x$.

Step2: Resolver la ecuación

Restar $\frac{1}{15}x$ de ambos lados: $5=\frac{2}{15}x-\frac{1}{15}x$. Como $\frac{2}{15}x-\frac{1}{15}x=\frac{2 - 1}{15}x=\frac{1}{15}x$, entonces $5=\frac{1}{15}x$. Multiplicar ambos lados por 15 para despejar $x$: $x = 75$.

Answer:

75