kelly is comparing two linear functions. - function g has a slope of \\(\\frac{1}{3}\\) and passes through…

kelly is comparing two linear functions. - function g has a slope of \\(\\frac{1}{3}\\) and passes through the point \\((0, -1)\\). - function h passes through the points \\((8, 3)\\) and \\((10, 4)\\). kelly says that the initial value of function g is greater than the initial value of function h. is kelly correct? use the drop - down menus to explain. click the arrows to choose an answer from each menu. function h has an initial value of choose... . the initial value of function g is choose... the initial value of function h. kelly is choose... .

kelly is comparing two linear functions. - function g has a slope of \\(\\frac{1}{3}\\) and passes through the point \\((0, -1)\\). - function h passes through the points \\((8, 3)\\) and \\((10, 4)\\). kelly says that the initial value of function g is greater than the initial value of function h. is kelly correct? use the drop - down menus to explain. click the arrows to choose an answer from each menu. function h has an initial value of choose... . the initial value of function g is choose... the initial value of function h. kelly is choose... .

Answer

Answer:

Function H has an initial value of $\boldsymbol{-1}$. The initial value of function G is $\boldsymbol{equal\ to}$ the initial value of function H. Kelly is $\boldsymbol{incorrect}$.

Explanation:

Step1: Find G's initial value

The initial value (y-intercept) of a linear function is the $y$-value when $x=0$. Function G passes through $(0,-1)$, so its initial value is $-1$.

Step2: Calculate H's slope

Use slope formula $m=\frac{y_2-y_1}{x_2-x_1}$. For points $(8,3)$ and $(10,4)$: $m=\frac{4-3}{10-8}=[LLM SSE On Failure]