kent multiplies both sides of the equation below by an expression.\n$k+\frac{12}{k}=8$\nthen he moves all…

kent multiplies both sides of the equation below by an expression.\n$k+\frac{12}{k}=8$\nthen he moves all the terms to one side of the equal sign in the resulting equation. which equation must he solve now?\n$k^{2}-8k - 12 = 0$\n$k^{2}+8k + 12 = 0$\n$k^{2}-8 + 12 = 0$\n$k^{2}-8k + 12 = 0$

kent multiplies both sides of the equation below by an expression.\n$k+\frac{12}{k}=8$\nthen he moves all the terms to one side of the equal sign in the resulting equation. which equation must he solve now?\n$k^{2}-8k - 12 = 0$\n$k^{2}+8k + 12 = 0$\n$k^{2}-8 + 12 = 0$\n$k^{2}-8k + 12 = 0$

Answer

Explanation:

Step1: Multiply both sides by k

Multiply $k+\frac{12}{k}=8$ by $k$ to get $k\times k + k\times\frac{12}{k}=8\times k$, which simplifies to $k^{2}+12 = 8k$.

Step2: Move terms to one - side

Subtract $8k$ from both sides: $k^{2}-8k + 12=0$.

Answer:

$k^{2}-8k + 12=0$