kuta software - infinite algebra 1\ngraphing lines\nsketch the graph of each line.\n1) $y = \\frac{7}{2}x - 2$

kuta software - infinite algebra 1\ngraphing lines\nsketch the graph of each line.\n1) $y = \\frac{7}{2}x - 2$

kuta software - infinite algebra 1\ngraphing lines\nsketch the graph of each line.\n1) $y = \\frac{7}{2}x - 2$

Answer

Explanation:

Step1: Identify the y - intercept

The equation is in slope - intercept form (y = mx + b), where (b) is the y - intercept. For (y=\frac{7}{2}x - 2), (b=-2). So the line crosses the y - axis at the point ((0,-2)).

Step2: Identify the slope

The slope (m=\frac{7}{2}). This means for every 2 units we move to the right along the x - axis, we move 7 units up along the y - axis.

Step3: Plot additional points

Starting from the y - intercept ((0,-2)), if we move 2 units to the right (x = 2), then (y=\frac{7}{2}\times2-2=7 - 2=5), so we have the point ((2,5)). We can also move 2 units to the left of the y - intercept (x=-2), then (y=\frac{7}{2}\times(-2)-2=-7 - 2=-9), giving the point ((-2,-9)).

Step4: Draw the line

Connect the points ((0,-2)), ((2,5)) and ((-2,-9)) with a straight line.

Answer:

Sketch a line that passes through the points ((0,-2)), ((2,5)) and ((-2,-9)) on the given coordinate grid.