layla is the youngest of four siblings whose ages are consecutive even integers. if the sum of their ages is…
layla is the youngest of four siblings whose ages are consecutive even integers. if the sum of their ages is 84, find laylas age.
Answer
Explanation:
Step1: Let Layla's age be $x$.
Since the ages are consecutive even integers, the other siblings' ages are $x + 2$, $x+4$, $x + 6$.
Step2: Set up the sum equation.
$x+(x + 2)+(x+4)+(x + 6)=84$.
Step3: Simplify the left - hand side.
Combining like terms, we get $4x+12 = 84$.
Step4: Solve for $x$.
Subtract 12 from both sides: $4x=84 - 12=72$. Then divide both sides by 4: $x=\frac{72}{4}=18$.
Answer:
18