y\\leq -x + 1\ny>x\n(-3,5)\n(-2,2)\n(-1,-3)\n(0,-1)

Explanation:

Step1: Check the first inequality for (-3,5)

Substitute x = - 3 and y = 5 into $y\leq -x + 1$. We get $5\leq-(-3)+1=3 + 1=4$, which is false.

Step2: Check the first inequality for (-2,2)

Substitute x=-2 and y = 2 into $y\leq -x + 1$. We get $2\leq-(-2)+1=2 + 1=3$, which is true. Then check the second - inequality $y>x$. Substitute x=-2 and y = 2, we get $2>-2$, which is true.

Step3: Check the first inequality for (-1,-3)

Substitute x=-1 and y=-3 into $y\leq -x + 1$. We get $-3\leq-(-1)+1=1 + 1=2$, which is true. Then check the second - inequality $y>x$. Substitute x=-1 and y=-3, we get $-3>-1$, which is false.

Step4: Check the first inequality for (0,-1)

Substitute x = 0 and y=-1 into $y\leq -x + 1$. We get $-1\leq-(0)+1=1$, which is true. Then check the second - inequality $y>x$. Substitute x = 0 and y=-1, we get $-1>0$, which is false.

Answer:

B. (-2,2)