let p: a number is greater than 25.\nlet q: a number is less than 35.\nif p ∧ q is true, then what could the…

let p: a number is greater than 25.\nlet q: a number is less than 35.\nif p ∧ q is true, then what could the number be? select two options.\n24\n28\n32\n36\n40

let p: a number is greater than 25.\nlet q: a number is less than 35.\nif p ∧ q is true, then what could the number be? select two options.\n24\n28\n32\n36\n40

Answer

Explanation:

Step1: Analyze the condition for (p\wedge q)

(p\wedge q) is true when both (p) (a number (x>25)) and (q) (a number (x < 35)) are true. So, we need to find (x) such that (25<x<35).

Step2: Check each option

  • For (x = 24), since (24\not>25), it does not satisfy (p\wedge q).
  • For (x=28), (25 < 28<35), so it satisfies (p\wedge q).
  • For (x = 32), (25<32<35), so it satisfies (p\wedge q).
  • For (x=36), since (36\not<35), it does not satisfy (p\wedge q).
  • For (x = 40), since (40\not<35), it does not satisfy (p\wedge q).

Answer:

28, 32