lets find $\frac{3}{4}+\frac{1}{6}$. first write the addition with a common denominator. then add…

lets find $\frac{3}{4}+\frac{1}{6}$. first write the addition with a common denominator. then add. $\frac{3}{4}+\frac{1}{6}=\frac{square}{square}+\frac{square}{square}=\frac{square}{square}$
Answer
Explanation:
Step1: Find common denominator
The least - common multiple of 4 and 6 is 12.
Step2: Rewrite fractions with common denominator
$\frac{3}{4}=\frac{3\times3}{4\times3}=\frac{9}{12}$ and $\frac{1}{6}=\frac{1\times2}{6\times2}=\frac{2}{12}$.
Step3: Add the fractions
$\frac{9}{12}+\frac{2}{12}=\frac{9 + 2}{12}=\frac{11}{12}$
Answer:
$\frac{9}{12}+\frac{2}{12}=\frac{11}{12}$