lets find $\frac{3}{4}-\frac{1}{6}$. first write the subtraction with a common denominator. then subtract…

lets find $\frac{3}{4}-\frac{1}{6}$. first write the subtraction with a common denominator. then subtract. $\frac{3}{4}-\frac{1}{6}=\frac{square}{square}-\frac{square}{square}=\frac{square}{square}$

lets find $\frac{3}{4}-\frac{1}{6}$. first write the subtraction with a common denominator. then subtract. $\frac{3}{4}-\frac{1}{6}=\frac{square}{square}-\frac{square}{square}=\frac{square}{square}$

Answer

Explanation:

Step1: Find common denominator

The least - common multiple of 4 and 6 is 12. Rewrite the fractions: $\frac{3}{4}=\frac{3\times3}{4\times3}=\frac{9}{12}$ and $\frac{1}{6}=\frac{1\times2}{6\times2}=\frac{2}{12}$.

Step2: Subtract the fractions

$\frac{9}{12}-\frac{2}{12}=\frac{9 - 2}{12}=\frac{7}{12}$

Answer:

$\frac{7}{12}$