lets find $\frac{2}{3}-\frac{1}{4}$. first write the subtraction with a common denominator. then subtract…

lets find $\frac{2}{3}-\frac{1}{4}$. first write the subtraction with a common denominator. then subtract. $\frac{2}{3}-\frac{1}{4}=\frac{square}{square}-\frac{square}{square}=\frac{square}{square}$

lets find $\frac{2}{3}-\frac{1}{4}$. first write the subtraction with a common denominator. then subtract. $\frac{2}{3}-\frac{1}{4}=\frac{square}{square}-\frac{square}{square}=\frac{square}{square}$

Answer

Explanation:

Step1: Find common denominator

The common - denominator of 3 and 4 is (3\times4 = 12).

Step2: Rewrite fractions

Rewrite (\frac{2}{3}) as (\frac{2\times4}{3\times4}=\frac{8}{12}) and (\frac{1}{4}) as (\frac{1\times3}{4\times3}=\frac{3}{12}). So (\frac{2}{3}-\frac{1}{4}=\frac{8}{12}-\frac{3}{12}).

Step3: Subtract numerators

(\frac{8}{12}-\frac{3}{12}=\frac{8 - 3}{12}=\frac{5}{12})

Answer:

(\frac{5}{12})